7213bec886
Summary: This makes Gid the same as the one in storage/v2. Before they can be merge into one implementation, we probably want to have a similar transition for remaining ID types. Depends on D2346 Reviewers: mferencevic, ipaljak Reviewed By: mferencevic Subscribers: pullbot Differential Revision: https://phabricator.memgraph.io/D2347
77 lines
2.2 KiB
C++
77 lines
2.2 KiB
C++
#include <vector>
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#include <gtest/gtest.h>
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#include "storage/common/mvcc/version.hpp"
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#include "storage/single_node/mvcc/record.hpp"
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#include "storage/single_node/mvcc/version_list.hpp"
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#include "transactions/single_node/engine.hpp"
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#include "transactions/transaction.hpp"
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#include "utils/thread/sync.hpp"
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#include "mvcc_gc_common.hpp"
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TEST(MVCC, Deadlock) {
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tx::Engine engine;
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auto t0 = engine.Begin();
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mvcc::VersionList<Prop> version_list1(*t0, storage::Gid::FromInt(0));
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mvcc::VersionList<Prop> version_list2(*t0, storage::Gid::FromInt(1));
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engine.Commit(*t0);
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auto t1 = engine.Begin();
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auto t2 = engine.Begin();
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version_list1.update(*t1);
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version_list2.update(*t2);
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EXPECT_THROW(version_list1.update(*t2), utils::LockTimeoutException);
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}
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// TODO Gleich: move this test to mvcc_gc???
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// check that we don't delete records when we re-link
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TEST(MVCC, UpdateDontDelete) {
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std::atomic<int> count{0};
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{
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tx::Engine engine;
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auto t1 = engine.Begin();
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mvcc::VersionList<DestrCountRec> version_list(*t1, storage::Gid::FromInt(0),
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count);
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engine.Commit(*t1);
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auto t2 = engine.Begin();
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version_list.update(*t2);
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engine.Abort(*t2);
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EXPECT_EQ(count, 0);
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auto t3 = engine.Begin();
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// Update re-links the node and shouldn't clear it yet.
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version_list.update(*t3);
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EXPECT_EQ(count, 0);
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// TODO Gleich: why don't we also test that remove doesn't delete?
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engine.Commit(*t3);
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}
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EXPECT_EQ(count, 3);
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}
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// Check that we get the oldest record.
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TEST(MVCC, Oldest) {
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tx::Engine engine;
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auto t1 = engine.Begin();
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mvcc::VersionList<Prop> version_list(*t1, storage::Gid::FromInt(0));
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auto first = version_list.Oldest();
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EXPECT_NE(first, nullptr);
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// TODO Gleich: no need to do 10 checks of the same thing
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for (int i = 0; i < 10; ++i) {
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engine.Advance(t1->id_);
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version_list.update(*t1);
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EXPECT_EQ(version_list.Oldest(), first);
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}
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// TODO Gleich: what about remove?
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// TODO Gleich: here it might make sense to write a concurrent test
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// since these ops rely heavily on linkage atomicity?
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}
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// TODO Gleich: perhaps some concurrent VersionList::find tests?
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