memgraph/src/utils/cast.hpp

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2022-02-22 20:33:45 +08:00
// Copyright 2022 Memgraph Ltd.
//
// Use of this software is governed by the Business Source License
// included in the file licenses/BSL.txt; by using this file, you agree to be bound by the terms of the Business Source
// License, and you may not use this file except in compliance with the Business Source License.
//
// As of the Change Date specified in that file, in accordance with
// the Business Source License, use of this software will be governed
// by the Apache License, Version 2.0, included in the file
// licenses/APL.txt.
#pragma once
#include <cstdint>
#include <cstring>
#include <type_traits>
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namespace memgraph::utils {
template <typename T>
constexpr typename std::underlying_type<T>::type UnderlyingCast(T e) {
return static_cast<typename std::underlying_type<T>::type>(e);
}
/**
* uint to int conversion in C++ is a bit tricky. Take a look here
* https://stackoverflow.com/questions/14623266/why-cant-i-reinterpret-cast-uint-to-int
* for more details.
*
* @tparam TDest Returned datatype.
* @tparam TSrc Input datatype.
*
* @return "copy casted" value.
*/
template <typename TDest, typename TSrc>
TDest MemcpyCast(TSrc src) {
TDest dest;
static_assert(sizeof(dest) == sizeof(src), "MemcpyCast expects source and destination to be of same size");
static_assert(std::is_arithmetic<TSrc>::value, "MemcpyCast expects source is an arithmetic type");
static_assert(std::is_arithmetic<TDest>::value, "MemcypCast expects destination is an arithmetic type");
std::memcpy(&dest, &src, sizeof(src));
return dest;
}
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} // namespace memgraph::utils