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5a76c5d2f3
* tccpp.c (parse_number): `shift' should be 1 while parsing binary floating point number. * tests/tests2/70_floating_point_literals.c: New test cases for floating point number parsing.
78 lines
2.0 KiB
C
78 lines
2.0 KiB
C
#include <stdio.h>
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int main()
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{
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/* decimal floating constant */
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float fa0 = .123f;
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float fa1 = .123E12F;
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float fa2 = .123e-12f;
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float fa3 = .123e+12f;
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printf("%f\n%f\n%f\n%f\n\n", fa0, fa1, fa2, fa3);
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float fb0 = 123.123f;
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float fb1 = 123.123E12F;
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float fb2 = 123.123e-12f;
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float fb3 = 123.123e+12f;
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printf("%f\n%f\n%f\n%f\n\n", fb0, fb1, fb2, fb3);
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float fc0 = 123.f;
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float fc1 = 123.E12F;
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float fc2 = 123.e-12f;
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float fc3 = 123.e+12f;
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printf("%f\n%f\n%f\n%f\n\n", fc0, fc1, fc2, fc3);
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float fd0 = 123E12F;
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float fd1 = 123e-12f;
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float fd2 = 123e+12f;
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printf("%f\n%f\n%f\n\n", fd0, fd1, fd2);
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printf("\n");
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/* hexadecimal floating constant */
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double da0 = 0X.1ACP12;
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double da1 = 0x.1acp-12;
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double da2 = 0x.1acp+12;
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printf("%f\n%f\n%f\n\n", da0, da1, da2);
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double db0 = 0X1AC.BDP12;
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double db1 = 0x1ac.bdp-12;
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double db2 = 0x1ac.dbp+12;
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printf("%f\n%f\n%f\n\n", db0, db1, db2);
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double dc0 = 0X1AC.P12;
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double dc1 = 0x1ac.p-12;
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double dc2 = 0x1ac.p+12;
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printf("%f\n%f\n%f\n\n", dc0, dc1, dc2);
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double dd0 = 0X1ACP12;
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double dd1 = 0x1acp-12;
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double dd2 = 0x1acp+12;
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printf("%f\n%f\n%f\n\n", dd0, dd1, dd2);
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printf("\n");
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#ifdef __TINYC__
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/* TCC extension
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binary floating constant */
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long double la0 = 0B.110101100P12L;
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long double la1 = 0b.110101100p-12l;
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long double la2 = 0b.110101100p+12l;
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printf("%Lf\n%Lf\n%Lf\n\n", la0, la1, la2);
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long double lb0 = 0B110101100.10111101P12L;
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long double lb1 = 0b110101100.10111101p-12l;
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long double lb2 = 0b110101100.10111101p+12l;
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printf("%Lf\n%Lf\n%Lf\n\n", lb0, lb1, lb2);
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long double lc0 = 0B110101100.P12L;
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long double lc1 = 0b110101100.p-12l;
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long double lc2 = 0b110101100.p+12l;
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printf("%Lf\n%Lf\n%Lf\n\n", lc0, lc1, lc2);
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long double ld0 = 0B110101100P12L;
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long double ld1 = 0b110101100p-12l;
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long double ld2 = 0b110101100p+12l;
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printf("%Lf\n%Lf\n%Lf\n\n", ld0, ld1, ld2);
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#endif
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return 0;
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}
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