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struct-init: Allow member initialization from qualified lvalues
See testcase.
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parent
9e86ebee94
commit
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5
tccgen.c
5
tccgen.c
@ -6012,7 +6012,10 @@ static void decl_initializer(CType *type, Section *sec, unsigned long c,
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if (have_elem &&
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!(type->t & VT_ARRAY) &&
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is_compatible_types(type, &vtop->type)) {
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/* Use i_c_parameter_t, to strip toplevel qualifiers.
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The source type might have VT_CONSTANT set, which is
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of course assignable to a non-const elements. */
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is_compatible_parameter_types(type, &vtop->type)) {
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init_putv(type, sec, c);
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} else if (type->t & VT_ARRAY) {
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s = type->ref;
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@ -96,6 +96,19 @@ struct Anon gan = { 10, 11 }; // ... which makes it available here.
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union UV2 guv4 = {{4,3}}; // and the other inits from above as well
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*/
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struct in6_addr {
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union {
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u8 u6_addr8[16];
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unsigned short u6_addr16[8];
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} u;
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};
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struct flowi6 {
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struct in6_addr saddr, daddr;
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};
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struct pkthdr {
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struct in6_addr daddr, saddr;
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};
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struct pkthdr phdr = { { { 6,5,4,3 } }, { { 9,8,7,6 } } };
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#include <stdio.h>
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void print_ (const char *name, const u8 *p, long size)
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{
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@ -107,7 +120,7 @@ void print_ (const char *name, const u8 *p, long size)
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}
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#define print(x) print_(#x, (u8*)&x, sizeof (x))
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#if 1
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void foo (struct W *w)
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void foo (struct W *w, struct pkthdr *phdr_)
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{
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struct S ls = {1, 2, 3, 4};
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struct S ls2 = {1, 2, {3, 4}};
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@ -115,6 +128,9 @@ void foo (struct W *w)
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struct U lu = {3, 5,6,7,8, 4, "huhu", 43};
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struct U lu1 = {3, ls, 4, {"huhu", 43}};
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struct U lu2 = {3, (ls), 4, {"huhu", 43}};
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const struct S *pls = &ls;
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struct S ls21 = *pls;
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struct U lu22 = {3, *pls, 4, {"huhu", 43}};
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/* Incomplete bracing. */
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struct U lu21 = {3, ls, 4, "huhu", 43};
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/* Optional braces around scalar initializers. Accepted, but with
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@ -129,20 +145,25 @@ void foo (struct W *w)
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/* Compund literal */
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struct V lv2 = {(struct S)w->t.s, {"hihi", 47}, 48};
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/* Parens around compound literal */
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struct V lv3 = {((struct S){7,8,{9,10}}), w->t.t, 50};
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struct V lv3 = {((struct S){7,8,{9,10}}), ((const struct W *)w)->t.t, 50};
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const struct pkthdr *phdr = phdr_;
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struct flowi6 flow = { .daddr = phdr->daddr, .saddr = phdr->saddr };
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print(ls);
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print(ls2);
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print(lt);
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print(lu);
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print(lu1);
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print(lu2);
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print(ls21);
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print(lu21);
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print(lu22);
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print(lu3);
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print(lu4);
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print(ls3);
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print(lv);
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print(lv2);
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print(lv3);
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print(flow);
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}
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#endif
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@ -167,7 +188,8 @@ int main()
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print(guv.b);
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print(guv2);
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print(guv3);
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foo(&gw);
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print(phdr);
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foo(&gw, &phdr);
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//printf("q: %s\n", q);
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return 0;
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}
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@ -17,16 +17,20 @@ guv: 6 5 0 0
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guv.b: 5
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guv2: 8 7 0 0
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guv3: 7 8 0 0
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phdr: 6 5 4 3 0 0 0 0 0 0 0 0 0 0 0 0 9 8 7 6 0 0 0 0 0 0 0 0 0 0 0 0
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ls: 1 2 3 4
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ls2: 1 2 3 4
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lt: 68 65 6c 6c 6f 0 0 0 0 0 0 0 0 0 0 0 2a
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lu: 3 5 6 7 8 4 68 75 68 75 0 0 0 0 0 0 0 0 0 0 0 0 2b
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lu1: 3 1 2 3 4 4 68 75 68 75 0 0 0 0 0 0 0 0 0 0 0 0 2b
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lu2: 3 1 2 3 4 4 68 75 68 75 0 0 0 0 0 0 0 0 0 0 0 0 2b
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ls21: 1 2 3 4
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lu21: 3 1 2 3 4 4 68 75 68 75 0 0 0 0 0 0 0 0 0 0 0 0 2b
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lu22: 3 1 2 3 4 4 68 75 68 75 0 0 0 0 0 0 0 0 0 0 0 0 2b
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lu3: 3 5 6 7 8 4 68 75 68 75 0 0 0 0 0 0 0 0 0 0 0 0 2b
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lu4: 3 5 6 7 0 5 62 6c 61 0 0 0 0 0 0 0 0 0 0 0 0 0 2c
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ls3: 1 2 3 4
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lv: 3 4 5 6 68 61 68 61 0 0 0 0 0 0 0 0 0 0 0 0 2d 2e
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lv2: 1 2 3 4 68 69 68 69 0 0 0 0 0 0 0 0 0 0 0 0 2f 30
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lv3: 7 8 9 a 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 32
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flow: 9 8 7 6 0 0 0 0 0 0 0 0 0 0 0 0 6 5 4 3 0 0 0 0 0 0 0 0 0 0 0 0
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