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fix(docs/other/bvid_desc.md) (#663)

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zine_yu 2023-05-15 02:25:58 +08:00 committed by GitHub
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@ -25,13 +25,15 @@
## 算法概述 ## 算法概述
算法以及程序主要参考[知乎@mcfx的回答](https://www.zhihu.com/question/381784377/answer/1099438784) ~~算法以及程序主要参考[知乎@mcfx的回答](https://www.zhihu.com/question/381784377/answer/1099438784)~~
实际上该算法并不完整,新的算法参考自[【揭秘】av号转bv号的过程](https://www.bilibili.com/video/BV1N741127Tj)
### av->bv算法 ### av->bv算法
注：本算法及示例程序仅能编解码`avid < 29460791296`，且暂无法验证`avid >= 29460791296`的正确性 注：本算法及示例程序仅能编解码`avid < 29460791296`，且暂无法验证`avid >= 29460791296`的正确性
再注：本人不清楚新算法能否编解码`avid >= 29460791296`
1. a = (avid ⊕ 177451812) + 8728348608 1. a = (avid ⊕ 177451812) + 100618342136696320
2. 以 i 为循环变量循环 6 次 b[i] = (a / 58 ^ i) % 58 2. 以 i 为循环变量循环 6 次 b[i] = (a / 58 ^ i) % 58
3. 将 b[i] 中各个数字转换为以下码表中的字符 3. 将 b[i] 中各个数字转换为以下码表中的字符
@ -39,23 +41,31 @@
> fZodR9XQDSUm21yCkr6zBqiveYah8bt4xsWpHnJE7jL5VG3guMTKNPAwcF > fZodR9XQDSUm21yCkr6zBqiveYah8bt4xsWpHnJE7jL5VG3guMTKNPAwcF
4. 初始化字符串 b[i]=`BV1 4 1 7 ` 4. 初始化字符串 b[i]=` `
5. 按照以下字符顺序编码表编码并填充至 b[i] 5. 按照以下字符顺序编码表编码并填充至 b[i]
字符顺序编码表： 字符顺序编码表：
> 0 -> 11 > 0 -> 9
> >
> 1 -> 10 > 1 -> 8
> >
> 2 -> 3 > 2 -> 1
> >
> 3 -> 8 > 3 -> 6
> >
> 4 -> 4 > 4 -> 2
> >
> 5 -> 6 > 5 -> 4
>
> 6 -> 0
>
> 7 -> 7
>
> 8 -> 3
>
> 9 -> 5
### bv->av算法 ### bv->av算法
@ -66,41 +76,56 @@
使用 Python、C、TypeScript、Java、Kotlin 以及 Golang 等语言作为示例，欢迎社区提交更多例程 使用 Python、C、TypeScript、Java、Kotlin 以及 Golang 等语言作为示例，欢迎社区提交更多例程
注: 新算法只提供了Python版本
### Python ### Python
```python ```python
table = 'fZodR9XQDSUm21yCkr6zBqiveYah8bt4xsWpHnJE7jL5VG3guMTKNPAwcF' # 码表 XOR = 177451812
tr = {} # 反查码表 ADD = 100618342136696320
# 初始化反查码表 TABLE = "fZodR9XQDSUm21yCkr6zBqiveYah8bt4xsWpHnJE7jL5VG3guMTKNPAwcF"
for i in range(58): MAP = {
tr[table[i]] = i 0:9,
s = [11, 10, 3, 8, 4, 6] # 位置编码表 1:8,
XOR = 177451812 # 固定异或值 2:1,
ADD = 8728348608 # 固定加法值 3:6,
4:2,
5:4,
6:0,
7:7,
8:3,
9:5
}
def av2bv(av):
av = (av ^ XOR) + ADD
bv = [""]*10
for i in range(10):
bv[MAP[i]] = TABLE[(av//58**i)%58]
return "".join(bv)
def bv2av(x): def bv2av(bv):
r = 0 av = [""]*10
for i in range(6): s = 0
r += tr[x[s[i]]] * 58 ** i for i in range(10):
return (r - ADD) ^ XOR s += TABLE.find(bv[MAP[i]])*58**i
av=(s-ADD)^XOR
def av2bv(x): return(av)
x = (x ^ XOR) + ADD
r = list('BV1 4 1 7 ')
for i in range(6):
r[s[i]] = table[x // 58 ** i % 58]
return ''. join(r)
print(av2bv(170001)) def main():
print(bv2av('BV17x411w7KC')) while True:
mod = input("1.AV2BV\n2.BV2AV\n3.Exit\n你的选择:")
if mod == "1":
print("BV号是: BV"+av2bv(int(input("AV号是:"))))
elif mod == "2":
print("AV号是 AV"+str(bv2av(input("BV号是"))))
elif mod == "3":
break
else:
print("输入错误请重新输入")
main()
``` ```
输出为：
```
BV17x411w7KC
170001
```
### C ### C