bilibili-API-collect/other/bvid_desc.md

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# bvid说明
2020-03-23 B站推出了全新的稿件视频id“bvid”来接替之前的“avid”其用法与性质等价于“avid”
详见:
1. [【升级公告】AV号全面升级至BV号专栏](https://www.bilibili.com/read/cv5167957)
2. [【升级公告】AV号全面升级至BV号](https://www.bilibili.com/blackboard/activity-BV-PC.html)
## 格式:
“bvid”恒为长度为12的字符串前两个字母为大写“BV”后10个位base58计算结果
## 实质:
“bvid"为“avid”的base58编码可通过算法进行相互转化
## avid发放方式的变化
从2009-09-09 09:09:09 [av2](https://www.bilibili.com/video/av2)的发布到2020-03-28 19:45:02 [av99999999](https://www.bilibili.com/video/av99999999)的发布B站结束了以投稿时间为顺序的avid发放改为随机发放avid
~~暗示B站东方要完泪目~~
## av->bv算法
本算法及示例程序仅能编码及解码avid<` 29460791296 `无法验证avid>=` 29460791296 `的正确性
1. a=(avid⊕177451812)+8728348608
2. 以i为循环变量循环6次b[i]=(a/58^i)%58
3. 将b[i]中各个数字转换为以下码表中的字符
码表:
> fZodR9XQDSUm21yCkr6zBqiveYah8bt4xsWpHnJE7jL5VG3guMTKNPAwcF
4. 初始化字符串b[i]=`BV1 4 1 7 `
5. 按照以下字符顺序编码表编码并填充至b[i]
字符顺序编码表:
> 0 -> 11
>
> 1 -> 10
>
> 2 -> 3
>
> 3 -> 8
>
> 4 -> 4
>
> 5 -> 6
算法以及程序主要参考[知乎@mcfx的回答](https://www.zhihu.com/question/381784377/answer/1099438784)
## bv->av算法
为以上算法的逆运算
## 转换程序:
目前使用**Python**与**C**作为示例
### python
```python
table = 'fZodR9XQDSUm21yCkr6zBqiveYah8bt4xsWpHnJE7jL5VG3guMTKNPAwcF' #码表
tr = {} #反查码表
#初始化反查码表
for i in range(58):
tr[table[i]] = i
s = [11, 10, 3, 8, 4, 6] #位置编码表
xor = 177451812 #固定异或值
add = 8728348608 #固定加法值
def bv2av(x):
r = 0
for i in range(6):
r += tr[x[s[i]]] * 58 ** i
return (r - add) ^ xor
def av2bv(x):
x = (x ^ xor) + add
r = list('BV1 4 1 7 ')
for i in range(6):
r[s[i]] = table[x // 58 ** i % 58]
return ''. join(r)
print(av2bv(170001))
print(bv2av('BV17x411w7KC'))
```
输出为:
```
BV17x411w7KC
170001
```
### C语言
```c
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
const char table[] = "fZodR9XQDSUm21yCkr6zBqiveYah8bt4xsWpHnJE7jL5VG3guMTKNPAwcF"; //码表
char tr[124]; //反查码表
const unsigned long long Xor = 177451812; //固定异或值
const unsigned long long add = 8728348608; //固定加法值
const int s[] = {11, 10, 3, 8, 4, 6}; //位置编码表
//初始化反查码表
void tr_init() {
for (int i = 0; i < 58; i++)
tr[table[i]] = i;
}
unsigned long long bv2av(char bv[]) {
unsigned long long r = 0;
unsigned long long av;
for (int i = 0; i < 6; i++)
r += tr[bv[s[i]]] * (unsigned long long)pow(58, i);
av = (r - add) ^ Xor;
return av;
}
char* av2bv(unsigned long long av) {
char* result = (char*)malloc(13);
strcpy(result,"BV1 4 1 7 ");
av = (av ^ Xor) + add;
for (int i = 0; i < 6; i++)
result[s[i]] = table[(unsigned long long)(av / (unsigned long long)pow(58, i)) % 58];
return result;
}
int main() {
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tr_init();
printf("%s\n",av2bv(170001));
printf("%u\n",bv2av("BV17x411w7KC"));
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return 0;
}
```
输出为:
```
BV17x411w7KC
170001
```