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sources/tech/20190920 How to compare strings in Java.md
448 lines
14 KiB
Markdown
448 lines
14 KiB
Markdown
[#]: collector: (lujun9972)
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[#]: translator: ( )
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[#]: reviewer: ( )
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[#]: publisher: ( )
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[#]: url: ( )
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[#]: subject: (How to compare strings in Java)
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[#]: via: (https://opensource.com/article/19/9/compare-strings-java)
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[#]: author: (Girish Managoli https://opensource.com/users/gammayhttps://opensource.com/users/sethhttps://opensource.com/users/clhermansenhttps://opensource.com/users/clhermansen)
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How to compare strings in Java
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======
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There are six ways to compare strings in Java.
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![Javascript code close-up with neon graphic overlay][1]
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String comparison is a fundamental operation in programming and is often quizzed during interviews. These strings are a sequence of characters that are _immutable_ which means unchanging over time or unable to be changed.
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Java has a number of methods for comparing strings; this article will teach you the primary operation of how to compare strings in Java.
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There are six options:
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1. The == operator
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2. String equals
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3. String equalsIgnoreCase
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4. String compareTo
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5. String compareToIgnoreCase
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6. Objects equals
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### The == operator
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**==** is an operator that returns **true** if the contents being compared refer to the same memory or **false** if they don't. If two strings compared with **==** refer to the same string memory, the return value is **true**; if not, it is **false**.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string2 = "YOURTEXT";
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[System][3].out.println("Output: " + (string1 == string2));
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Output: false
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```
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The return value of **==** above is **false**, as "MYTEXT" and "YOURTEXT" refer to different memory.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string6 = "MYTEXT";
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[System][3].out.println("Output: " + (string1 == string6));
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Output: true
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```
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In this case, the return value of **==** is **true**, as the compiler internally creates one memory location for both "MYTEXT" memories, and both variables refer to the same memory location.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string7 = string1;
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[System][3].out.println("Output: " + (string1 == string7));
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Output: true
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```
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If you guessed right, you know string7 is initialized with the same memory location as string1 and therefore **==** is true.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string4 = new [String][2]("MYTEXT");
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[System][3].out.println("Output: " + (string1 == string4));
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Output: false
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```
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In this case, the compiler creates a new memory location, even though the value is the same for string4 and string1.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string5 = new [String][2](string1);
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[System][3].out.println("Output: " + (string1 == string4));
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Output: false
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```
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Here, string5 is a new string object initialized with string1; hence, **string1 == string4** is not true.
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### String equals
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The string class has a **String equals** method to compare two strings. String comparison with **equals** is case-sensitive. According to the [docs][4]:
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```
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/**
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* Compares this string to the specified object. The result is {@code
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* true} if and only if the argument is not {@code null} and is a {@code
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* String} object that represents the same sequence of characters as this
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* object.
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*
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* @param anObject
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* The object to compare this {@code String} against
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*
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* @return {@code true} if the given object represents a {@code String}
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* equivalent to this string, {@code false} otherwise
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*
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* @see #compareTo(String)
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* @see #equalsIgnoreCase(String)
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*/
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public boolean equals(Object anObject) { ... }
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```
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Let's see a few examples:
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string2 = "YOURTEXT";
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[System][3].out.println("Output: " + string1.equals(string2));
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Output: false
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```
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If the strings are not the same, the output of the **equals** method is obviously **false**.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string3 = "mytext";
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[System][3].out.println("Output: " + string1.equals(string3));
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Output: false
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```
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These strings are the same in value but differ in case; hence, the output is **false**.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string4 = new [String][2]("MYTEXT");
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[System][3].out.println("Output: " + string1.equals(string4));
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Output: true
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[/code] [code]
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[String][2] string1 = "MYTEXT";
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[String][2] string5 = new [String][2](string1);
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[System][3].out.println("Output: " + string1.equals(string5));
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Output: true
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```
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The examples in both these cases are **true**, as the two values are the same. Unlike with **==**, the second example above returns **true**.
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The string object on which **equals** is called should obviously be a valid string object and non-null.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string8 = null;
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[System][3].out.println("Output: " + string8.equals(string1));
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[Exception][5] in thread _____ java.lang.[NullPointerException][6]
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```
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The above evidently is not a good code.
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```
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[System][3].out.println("Output: " + string1.equals(string8));
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Output: false
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```
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This is alright.
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### String equalsIgnoreCase
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The behavior of **equalsIgnoreCase** is identical to **equals** with one difference—the comparison is not case-sensitive. The [docs][4] say:
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```
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/**
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* Compares this {@code String} to another {@code String}, ignoring case
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* considerations. Two strings are considered equal ignoring case if they
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* are of the same length and corresponding characters in the two strings
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* are equal ignoring case.
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*
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* <p> Two characters {@code c1} and {@code c2} are considered the same
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* ignoring case if at least one of the following is true:
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* <ul>
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* <li> The two characters are the same (as compared by the
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* {@code ==} operator)
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* <li> Applying the method {@link
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* java.lang.Character#toUpperCase(char)} to each character
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* produces the same result
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* <li> Applying the method {@link
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* java.lang.Character#toLowerCase(char)} to each character
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* produces the same result
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* </ul>
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*
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* @param anotherString
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* The {@code String} to compare this {@code String} against
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*
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* @return {@code true} if the argument is not {@code null} and it
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* represents an equivalent {@code String} ignoring case; {@code
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* false} otherwise
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*
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* @see #equals(Object)
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*/
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public boolean equalsIgnoreCase(String anotherString) { ... }
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```
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The second example in **equals** (above) is the only difference from the comparison in **equalsIgnoreCase**.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string3 = "mytext";
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[System][3].out.println("Output: " + string1.equalsIgnoreCase(string3));
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Output: true
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```
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This returns **true** because the comparison is case-independent. All other examples under **equals** remain the same as they are for **equalsIgnoreCase**.
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### String compareTo
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The **compareTo** method compares two strings lexicographically (i.e., pertaining to alphabetical order) and case-sensitively and returns the lexicographical difference in the two strings. The [docs][4] describe lexicographical order computation as:
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```
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/**
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* Compares two strings lexicographically.
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* The comparison is based on the Unicode value of each character in
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* the strings. The character sequence represented by this
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* {@code String} object is compared lexicographically to the
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* character sequence represented by the argument string. The result is
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* a negative integer if this {@code String} object
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* lexicographically precedes the argument string. The result is a
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* positive integer if this {@code String} object lexicographically
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* follows the argument string. The result is zero if the strings
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* are equal; {@code compareTo} returns {@code 0} exactly when
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* the {@link #equals(Object)} method would return {@code true}.
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* <p>
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* This is the definition of lexicographic ordering. If two strings are
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* different, then either they have different characters at some index
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* that is a valid index for both strings, or their lengths are different,
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* or both. If they have different characters at one or more index
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* positions, let <i>k</i> be the smallest such index; then the string
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* whose character at position <i>k</i> has the smaller value, as
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* determined by using the &lt; operator, lexicographically precedes the
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* other string. In this case, {@code compareTo} returns the
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* difference of the two character values at position {@code k} in
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* the two string -- that is, the value:
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* <blockquote><pre>
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* this.charAt(k)-anotherString.charAt(k)
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* </pre></blockquote>
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* If there is no index position at which they differ, then the shorter
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* string lexicographically precedes the longer string. In this case,
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* {@code compareTo} returns the difference of the lengths of the
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* strings -- that is, the value:
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* <blockquote><pre>
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* this.length()-anotherString.length()
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* </pre></blockquote>
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*
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* @param anotherString the {@code String} to be compared.
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* @return the value {@code 0} if the argument string is equal to
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* this string; a value less than {@code 0} if this string
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* is lexicographically less than the string argument; and a
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* value greater than {@code 0} if this string is
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* lexicographically greater than the string argument.
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*/
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public int compareTo(String anotherString) { ... }
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```
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Let's look at some examples.
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```
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[String][2] string1 = "A";
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[String][2] string2 = "B";
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[System][3].out.println("Output: " + string1.compareTo(string2));
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Output: -1
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[System][3].out.println("Output: " + string2.compareTo(string1));
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Output: 1
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[/code] [code]
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[String][2] string1 = "A";
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[String][2] string3 = "a";
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[System][3].out.println("Output: " + string1.compareTo(string3));
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Output: -32
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[System][3].out.println("Output: " + string3.compareTo(string1));
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Output: 32
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[/code] [code]
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[String][2] string1 = "A";
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[String][2] string6 = "A";
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[System][3].out.println("Output: " + string1.compareTo(string6));
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Output: 0
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[/code] [code]
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String string1 = "A";
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String string8 = null;
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System.out.println("Output: " + string8.compareTo(string1));
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Exception in thread ______ java.lang.NullPointerException
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at java.lang.String.compareTo(String.java:1155)
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String string1 = "A";
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String string10 = "";
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System.out.println("Output: " + string1.compareTo(string10));
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Output: 1
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```
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### String compareToIgnoreCase
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The behavior of **compareToIgnoreCase** is identical to **compareTo** with one difference: the strings are compared without case consideration.
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```
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[String][2] string1 = "A";
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[String][2] string3 = "a";
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[System][3].out.println("Output: " + string1.compareToIgnoreCase(string3));
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Output: 0
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```
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### Objects equals
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The **Objects equals** method invokes the overridden **String equals** method; its behavior is the same as in the **String equals** example above.
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```
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[String][2] string1 = "MYTEXT";
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[String][2] string2 = "YOURTEXT";
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[System][3].out.println("Output: " + Objects(string1, string2));
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Output: false
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[/code] [code]
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[String][2] string1 = "MYTEXT";
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[String][2] string3 = "mytext";
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[System][3].out.println("Output: " + Objects(string1, string3));
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Output: false
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[/code] [code]
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[String][2] string1 = "MYTEXT";
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[String][2] string6 = "MYTEXT";
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[System][3].out.println("Output: " + Objects(string1, string6));
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Output: true
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[/code] [code]
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[String][2] string1 = "MYTEXT";
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[String][2] string8 = null;
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[System][3].out.println("Output: " + Objects.equals(string1, string8));
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Output: false
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[System][3].out.println("Output: " + Objects.equals(string8, string1));
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Output: false
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[/code] [code]
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[String][2] string8 = null;
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[String][2] string9 = null;
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[System][3].out.println("Output: " + Objects.equals(string8, string9));
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Output: true
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```
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The advantage here is that the **Objects equals** method checks for null values (unlike **String equals**). The implementation of **Object equals** is:
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```
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public static boolean equals([Object][7] a, [Object][7] b) {
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return (a == b) || (a != null && a.equals(b));
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}
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```
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### Which method to use?
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There are many methods to compare two strings. Which one should you use? As a common practice, use **String equals** for case-sensitive strings and **String equalsIgnoreCase** for case-insensitive comparisons. However, one caveat: take care of NPE (**NullPointerException**) if one or both strings are null.
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The source code is available on [GitLab][8] and [GitHub][9].
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--------------------------------------------------------------------------------
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via: https://opensource.com/article/19/9/compare-strings-java
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作者:[Girish Managoli][a]
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选题:[lujun9972][b]
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译者:[译者ID](https://github.com/译者ID)
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校对:[校对者ID](https://github.com/校对者ID)
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本文由 [LCTT](https://github.com/LCTT/TranslateProject) 原创编译,[Linux中国](https://linux.cn/) 荣誉推出
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[a]: https://opensource.com/users/gammayhttps://opensource.com/users/sethhttps://opensource.com/users/clhermansenhttps://opensource.com/users/clhermansen
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[b]: https://github.com/lujun9972
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[1]: https://opensource.com/sites/default/files/styles/image-full-size/public/lead-images/code_javascript.jpg?itok=60evKmGl (Javascript code close-up with neon graphic overlay)
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[2]: http://www.google.com/search?hl=en&q=allinurl%3Adocs.oracle.com+javase+docs+api+string
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[3]: http://www.google.com/search?hl=en&q=allinurl%3Adocs.oracle.com+javase+docs+api+system
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[4]: http://hg.openjdk.java.net/jdk8/jdk8/jdk/file/687fd7c7986d/src/share/classes/java/lang/String.java
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[5]: http://www.google.com/search?hl=en&q=allinurl%3Adocs.oracle.com+javase+docs+api+exception
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[6]: http://www.google.com/search?hl=en&q=allinurl%3Adocs.oracle.com+javase+docs+api+nullpointerexception
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[7]: http://www.google.com/search?hl=en&q=allinurl%3Adocs.oracle.com+javase+docs+api+object
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[8]: https://gitlab.com/gammay/stringcomparison
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[9]: https://github.com/gammay/stringcompare
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