Conditional Rendering in React using Ternaries and Logical AND
============================================================
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Photo by [Brendan Church][1] on [Unsplash][2]
There are several ways that your React component can decide what to render. You can use the traditional `if` statement or the `switch` statement. In this article, we’ll explore a few alternatives. But be warned that some come with their own gotchas, if you’re not careful.
### Ternary vs if/else
Let’s say we have a component that is passed a `name` prop. If the string is non-empty, we display a greeting. Otherwise we tell the user they need to sign in.
Here’s a Stateless Function Component (SFC) that does just that.
```
const MyComponent = ({ name }) => {
if (name) {
return (
` markup. 🎉
### Ternary vs Logical AND
As you can see, ternaries are wonderful for `if/else` conditions. But what about simple `if` conditions?
Let’s look at another example. If `isPro` (a boolean) is `true`, we are to display a trophy emoji. We are also to render the number of stars (if not zero). We could go about it like this.
```
const MyComponent = ({ name, isPro, stars}) => (
Hello {name}
{isPro ? '🏆' : null}
{stars ? (
Stars:{'⭐️'.repeat(stars)}
) : null}
);
```
But notice the “else” conditions return `null`. This is becasue a ternary expects an else condition.
For simple `if` conditions, we could use something a little more fitting: the logical AND operator. Here’s the same code written using a logical AND.
```
const MyComponent = ({ name, isPro, stars}) => (
Hello {name}
{isPro && '🏆'}
{stars && (
Stars:{'⭐️'.repeat(stars)}
)}
);
```
Not too different, but notice how we eliminated the `: null` (i.e. else condition) at the end of each ternary. Everything should render just like it did before.
Hey! What gives with John? There is a `0` when nothing should be rendered. That’s the gotcha that I was referring to above. Here’s why.
[According to MDN][3], a Logical AND (i.e. `&&`):
> `expr1 && expr2`
> Returns `expr1` if it can be converted to `false`; otherwise, returns `expr2`. Thus, when used with Boolean values, `&&` returns `true` if both operands are true; otherwise, returns `false`.
OK, before you start pulling your hair out, let me break it down for you.
In our case, `expr1` is the variable `stars`, which has a value of `0`. Because zero is falsey, `0` is returned and rendered. See, that wasn’t too bad.
I would write this simply.
> If `expr1` is falsey, returns `expr1`, else returns `expr2`.
So, when using a logical AND with non-boolean values, we must make the falsey value return something that React won’t render. Say, like a value of `false`.
There are a few ways that we can accomplish this. Let’s try this instead.
```
{!!stars && (
{'⭐️'.repeat(stars)}
)}
```
Notice the double bang operator (i.e. `!!`) in front of `stars`. (Well, actually there is no “double bang operator”. We’re just using the bang operator twice.)
The first bang operator will coerce the value of `stars` into a boolean and then perform a NOT operation. If `stars` is `0`, then `!stars` will produce `true`.
Then we perform a second NOT operation, so if `stars` is 0, `!!stars` would produce `false`. Exactly what we want.
If you’re not a fan of `!!`, you can also force a boolean like this (which I find a little wordy).
```
{Boolean(stars) && (
```
Or simply give a comparator that results in a boolean value (which some might say is even more semantic).
```
{stars > 0 && (
```
#### A word on strings
Empty string values suffer the same issue as numbers. But because a rendered empty string is invisible, it’s not a problem that you will likely have to deal with, or will even notice. However, if you are a perfectionist and don’t want an empty string on your DOM, you should take similar precautions as we did for numbers above.
### Another solution
A possible solution, and one that scales to other variables in the future, would be to create a separate `shouldRenderStars` variable. Then you are dealing with boolean values in your logical AND.
```
const shouldRenderStars = stars > 0;
```
```
return (
{shouldRenderStars && (
{'⭐️'.repeat(stars)}
)}
);
```
Then, if in the future, the business rule is that you also need to be logged in, own a dog, and drink light beer, you could change how `shouldRenderStars` is computed, and what is returned would remain unchanged. You could also place this logic elsewhere where it’s testable and keep the rendering explicit.
```
const shouldRenderStars =
stars > 0 && loggedIn && pet === 'dog' && beerPref === 'light`;
```
```
return (
{shouldRenderStars && (
{'⭐️'.repeat(stars)}
)}
);
```
### Conclusion
I’m of the opinion that you should make best use of the language. And for JavaScript, this means using conditional ternary operators for `if/else`conditions and logical AND operators for simple `if` conditions.
While we could just retreat back to our safe comfy place where we use the ternary operator everywhere, you now possess the knowledge and power to go forth AND prosper.
--------------------------------------------------------------------------------
作者简介:
Managing Editor at the American Express Engineering Blog http://aexp.io and Director of Engineering @AmericanExpress. MyViews !== ThoseOfMyEmployer.
----------------
via: https://medium.freecodecamp.org/conditional-rendering-in-react-using-ternaries-and-logical-and-7807f53b6935
作者:[Donavon West][a]
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[a]:https://medium.freecodecamp.org/@donavon
[1]:https://unsplash.com/photos/pKeF6Tt3c08?utm_source=unsplash&utm_medium=referral&utm_content=creditCopyText
[2]:https://unsplash.com/search/photos/road-sign?utm_source=unsplash&utm_medium=referral&utm_content=creditCopyText
[3]:https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Logical_Operators