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PUB:20151127 Linux or UNIX grep Command Tutorial series 5--Grep From Files and Display the File Name

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@runningwater 这篇你给忘记了吧~~
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sources/tech/Linux or UNIX grep Command Tutorial series/20151127 Linux or UNIX grep Command Tutorial series 5--Grep From Files and Display the File Name.md → published/20151127 Linux or UNIX grep Command Tutorial series 5--Grep From Files and Display the File Name.md
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(translating by runningwater)
Grep From Files and Display the File Name
grep 命令系列：从文件中搜索并显示文件名
================================================================================
How do I grep from a number of files and display the file name only?
When there is more than one file to search it will display file name by default:
我怎样从几个文件中搜索（grep），并只显示匹配到的文件的文件名？
grep "word" filename
当你从不止一个的文件中搜索时，默认它将显示文件名：
grep "word" 文件名
grep root /etc/*
Sample outputs:
示例输出：
/etc/bash.bashrc: See "man sudo_root" for details.
/etc/crontab:17 * * * * root cd / && run-parts --report /etc/cron.hourly
@ -20,12 +20,12 @@ Sample outputs:
/etc/logrotate.conf: create 0664 root utmp
/etc/logrotate.conf: create 0660 root utmp
The first name is file name (e.g., /etc/crontab, /etc/group). The -l option will only print filename if th
每行开始的第一个部分是文件名（如：/etc/crontab、/etc/group）。使用 -l 选项可以只显示文件名：
grep -l "string" filename
grep -l root /etc/*
Sample outputs:
示例输出：
/etc/aliases
/etc/arpwatch.conf
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/etc/crontab
/etc/group
You can suppress normal output; instead print the name of each input file from **which no output would normally have been** printed:
你也可以逆转输出；使用 -L 选项来输出**那些不匹配的文件的文件名**：
grep -L "word" filename
grep -L root /etc/*
Sample outputs:
示例输出：
/etc/apm
/etc/apparmor
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via: http://www.cyberciti.biz/faq/grep-from-files-and-display-the-file-name/
作者：Vivek Gite
译者：[runningwater](https://github.com/runningwater)
校对：[校对者ID](https://github.com/校对者ID)
译者：[wxy](https://github.com/wxy)
校对：[wxy](https://github.com/wxy)
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