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Update 5.RRefMovSemPerfForw/item28.md

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Co-authored-by: Yi Yang <1948638989@qq.com>
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standback 2021-09-28 17:29:37 +08:00 committed by Yi Yang
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@ -9,7 +9,7 @@ template<typename T>
void func(T&& param);
```
被推导的模板形参`T`将根据被传给`param`的实参为左值还是右值而被编码.
不管传给param的实参是左值还是右值，模板形参`T`都会编码。
编码机制是简单的。当左值实参被传入时，`T`被推导为左值引用。当右值被传入时，`T`被推导为非引用。（请注意不对称性：左值被编码为左值引用，右值被编码为**非引用**。）因此：