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fix: spell error: is_instegral -> is_integral (#115)

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sunyuhan19981208 2022-03-24 10:25:25 +08:00 committed by GitHub
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5.RRefMovSemPerfForw/item27.md
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@ -80,14 +80,14 @@ void logAndAdd(T&& name)
{
logAndAddImpl(
std::forward<T>(name),
std::is_instegral<typename std::remove_reference<T>::type>()
std::is_integral<typename std::remove_reference<T>::type>()
);
}
```
这个代码很巧妙。（在C++14中，你可以通过`std::remove_reference_t<T>`来简化写法，参看[Item9](https://github.com/kelthuzadx/EffectiveModernCppChinese/blob/master/3.MovingToModernCpp/item9.md)）
处理完之后，我们可以将注意力转移到名为`logAndAddImpl`的函数上了。有两个重载函数，第一个仅用于非整型类型（即`std::is_instegral<typename std::remove_reference<T>::type>`是false）：
处理完之后，我们可以将注意力转移到名为`logAndAddImpl`的函数上了。有两个重载函数，第一个仅用于非整型类型（即`std::is_integral<typename std::remove_reference<T>::type>`是false）：
```cpp
template<typename T> //非整型实参：添加到全局数据结构中