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< title > Item 9:优先考虑别名声明而非typedefs - Effective Modern C++< / title >
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2023-05-06 14:19:14 +08:00
< ol class = "chapter" > < li class = "chapter-item expanded " > < a href = "../Introduction.html" > 简介< / a > < / li > < li class = "chapter-item expanded " > < div > 第一章 类型推导< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item1.html" > Item 1:理解模板类型推导< / a > < / li > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item2.html" > Item 2:理解auto类型推导< / a > < / li > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item3.html" > Item 3:理解decltype< / a > < / li > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item4.html" > Item 4:学会查看类型推导结果< / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第二章 auto< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../2.Auto/item5.html" > Item 5:优先考虑auto而非显式类型声明< / a > < / li > < li class = "chapter-item expanded " > < a href = "../2.Auto/item6.html" > Item 6:auto推导若非己愿， < / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第三章 移步现代C++< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item7.html" > Item 7:区别使用()和{}创建对象< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item8.html" > Item 8:优先考虑nullptr而非0和NULL< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item9.html" class = "active" > Item 9:优先考虑别名声明而非typedefs< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item10.html" > Item 10:优先考虑限域枚举而非未限域枚举< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item11.html" > Item 11:优先考虑使用deleted函数而非使用未定义的私有声明< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item12.html" > Item 12:使用override声明重载函数< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item13.html" > Item 13:优先考虑const_iterator而非iterator< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item14.html" > Item 14:如果函数不抛出异常请使用noexcept< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item15.html" > Item 15:尽可能的使用constexpr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item16.html" > Item 16:让const成员函数线程安全< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item17.html" > Item 17:理解特殊成员函数函数的生成< / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第四章 智能指针< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item18.html" > Item 18:对于独占资源使用std::unique_ptr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item19.html" > Item 19:对于共享资源使用std::shared_ptr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item20.html" > Item 20:当std::shared_ptr可能悬空时使用std::weak_ptr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item21.html" > Item 21:优先考虑使用std::make_unique和std::make_shared而非new< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item22.html" > Item 22:当使用Pimpl惯用法， < / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第五章 右值引用，移动语义，完美转发< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../5.RRefMovSemPerfForw/item23.html" > Item 23:理解std::move和std::forward< / a > < / li > < li class = "chapter-item expanded " > < a href = "../5.RRefMovSemPerfForw/item24.html" > Item 24:区别通用引用和右值引用< / a > < / li > < li class = "chapter-item expanded " > < a href = "../5.RRefMovSemPerfForw/item25.html" > Item 25:对于右值引用使用std::move， < / a > < / li > < li class = "chapter-item expanded " > < a href = "../5
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2024-05-19 16:14:18 +08:00
< h2 id = "条款九优先考虑别名声明而非typedef" > < a class = "header" href = "#条款九优先考虑别名声明而非typedef" > 条款九：优先考虑别名声明而非< code > typedef< / code > < / a > < / h2 >
< p > < strong > Item 9: Prefer alias declarations to < code > typedef< / code > < / strong > < / p >
2022-11-25 13:43:31 +08:00
< p > 我相信每个人都同意使用STL容器是个好主意， < a href = "../4.SmartPointers/item18.html" > Item18< / a > 能说服你让你觉得使用< code > std:unique_ptr< / code > 也是个好主意，但我猜没有人喜欢写上几次 < code > std::unique_ptr< std::unordered_map< std::string, std::string> > < / code > 这样的类型，它可能会让你患上腕管综合征的风险大大增加。< / p >
2022-06-30 10:23:03 +08:00
< p > 避免上述医疗悲剧也很简单，引入< code > typedef< / code > 即可：< / p >
< pre > < code class = "language-cpp" > typedef
std::unique_ptr< std::unordered_map< std::string, std::string> >
UPtrMapSS;
< / code > < / pre >
< p > 但< code > typedef< / code > 是C++98的东西。虽然它可以在C++11中工作， （ < em > alias declaration< / em > ） ： < / p >
< pre > < code class = "language-cpp" > using UPtrMapSS =
std::unique_ptr< std::unordered_map< std::string, std::string> > ;
< / code > < / pre >
< p > 由于这里给出的< code > typedef< / code > 和别名声明做的都是完全一样的事情，我们有理由想知道会不会出于一些技术上的原因两者有一个更好。< / p >
< p > 这里，在说它们之前我想提醒一下很多人都发现当声明一个函数指针时别名声明更容易理解：< / p >
< pre > < code class = "language-cpp" > //FP是一个指向函数的指针的同义词，
//int和const std::string& 形参，不返回任何东西
typedef void (*FP)(int, const std::string& ); //typedef
//含义同上
using FP = void (*)(int, const std::string& ); //别名声明
< / code > < / pre >
< p > 当然，两个结构都不是非常让人满意，没有人喜欢花大量的时间处理函数指针类型的别名（译注：指< code > FP< / code > ），所以至少在这里，没有一个吸引人的理由让你觉得别名声明比< code > typedef< / code > 好。< / p >
< p > 不过有一个地方使用别名声明吸引人的理由是存在的：模板。特别地，别名声明可以被模板化（这种情况下称为别名模板< em > alias template< / em > s） < code > typedef< / code > 不能。这使得C++11程序员可以很直接的表达一些C++98中只能把< code > typedef< / code > 嵌套进模板化的< code > struct< / code > 才能表达的东西。考虑一个链表的别名，链表使用自定义的内存分配器，< code > MyAlloc< / code > 。使用别名模板，这真是太容易了：< / p >
< pre > < code class = "language-cpp" > template< typename T> //MyAllocList< T> 是
using MyAllocList = std::list< T, MyAlloc< T> > ; //std::list< T, MyAlloc< T> >
//的同义词
MyAllocList< Widget> lw; //用户代码
< / code > < / pre >
< p > 使用< code > typedef< / code > ，你就只能从头开始：< / p >
< pre > < code class = "language-cpp" > template< typename T> //MyAllocList< T> 是
struct MyAllocList { //std::list< T, MyAlloc< T> >
typedef std::list< T, MyAlloc< T> > type; //的同义词
};
MyAllocList< Widget> ::type lw; //用户代码
< / code > < / pre >
< p > 更糟糕的是，如果你想使用在一个模板内使用< code > typedef< / code > 声明一个链表对象，而这个对象又使用了模板形参，你就不得不在< code > typedef< / code > 前面加上< code > typename< / code > ： < / p >
< pre > < code class = "language-cpp" > template< typename T>
class Widget { //Widget< T> 含有一个
private: //MyAllocLIst< T> 对象
typename MyAllocList< T> ::type list; //作为数据成员
…
};
< / code > < / pre >
< p > 这里< code > MyAllocList< T> ::type< / code > 使用了一个类型，这个类型依赖于模板参数< code > T< / code > 。因此< code > MyAllocList< T> ::type< / code > 是一个依赖类型（< em > dependent type< / em > ） ， < code > typename< / code > 。< / p >
< p > 如果使用别名声明定义一个< code > MyAllocList< / code > ，就不需要使用< code > typename< / code > （同时省略麻烦的“< code > ::type< / code > ”后缀）：< / p >
< pre > < code class = "language-cpp" > template< typename T>
using MyAllocList = std::list< T, MyAlloc< T> > ; //同之前一样
template< typename T>
class Widget {
private:
MyAllocList< T> list; //没有“typename”
… //没有“::type”
};
< / code > < / pre >
< p > 对你来说，< code > MyAllocList< T> < / code > （使用了模板别名声明的版本）可能看起来和< code > MyAllocList< T> ::type< / code > （使用< code > typedef< / code > 的版本）一样都应该依赖模板参数< code > T< / code > ，但是你不是编译器。当编译器处理< code > Widget< / code > 模板时遇到< code > MyAllocList< T> < / code > （使用模板别名声明的版本），它们知道< code > MyAllocList< T> < / code > 是一个类型名，因为< code > MyAllocList< / code > 是一个别名模板：它< strong > 一定< / strong > 是一个类型名。因此< code > MyAllocList< T> < / code > 就是一个< strong > 非依赖类型< / strong > （ < em > non-dependent type< / em > ），就不需要也不允许使用< code > typename< / code > 修饰符。< / p >
< p > 当编译器在< code > Widget< / code > 的模板中看到< code > MyAllocList< T> ::type< / code > （使用< code > typedef< / code > 的版本），它不能确定那是一个类型的名称。因为可能存在一个< code > MyAllocList< / code > 的它们没见到的特化版本，那个版本的< code > MyAllocList< T> ::type< / code > 指代了一种不是类型的东西。那听起来很不可思议，但不要责备编译器穷尽考虑所有可能。因为人确实能写出这样的代码。< / p >
< p > 举个例子，一个误入歧途的人可能写出这样的代码：< / p >
< pre > < code class = "language-cpp" > class Wine { … };
template< > //当T是Wine
class MyAllocList< Wine> { //特化MyAllocList
private:
enum class WineType //参见Item10了解
{ White, Red, Rose }; //" enum class"
WineType type; //在这个类中，
… //一个数据成员！
};
< / code > < / pre >
< p > 就像你看到的，< code > MyAllocList< Wine> ::type< / code > 不是一个类型。如果< code > Widget< / code > 使用< code > Wine< / code > 实例化，在< code > Widget< / code > 模板中的< code > MyAllocList< Wine> ::type< / code > 将会是一个数据成员，不是一个类型。在< code > Widget< / code > 模板内，< code > MyAllocList< T> ::type< / code > 是否表示一个类型取决于< code > T< / code > 是什么，这就是为什么编译器会坚持要求你在前面加上< code > typename< / code > 。< / p >
2022-11-25 13:43:31 +08:00
< p > 如果你尝试过模板元编程（< em > template metaprogramming< / em > ， ） ， < code > T< / code > ，如果你想去掉< code > T< / code > 的常量修饰和引用修饰（< code > const< / code > - or reference qualifiers） ， < code > const std::string& < / code > 变成< code > std::string< / code > 。又或者你想给一个类型加上< code > const< / code > 或变为左值引用，比如把< code > Widget< / code > 变成< code > const Widget< / code > 或< code > Widget& < / code > 。（ ， ， ， < a href = "../5.RRefMovSemPerfForw/item23.html" > Item23< / a > ， < a href = "../5.RRefMovSemPerfForw/item27.html" > 27< / a > 里的TMP的应用实例， ） < / p >
2022-06-30 10:23:03 +08:00
< p > C++11在< em > type traits< / em > （类型特性）中给了你一系列工具去实现类型转换，如果要使用这些模板请包含头文件< code > < type_traits> < / code > 。里面有许许多多< em > type traits< / em > ，也不全是类型转换的工具，也包含一些可预测接口的工具。给一个你想施加转换的类型< code > T< / code > ，结果类型就是< code > std::< / code > transformation< code > < T> ::type< / code > ，比如：< / p >
< pre > < code class = "language-cpp" > std::remove_const< T> ::type //从const T中产出T
std::remove_reference< T> ::type //从T& 和T& & 中产出T
std::add_lvalue_reference< T> ::type //从T中产出T&
< / code > < / pre >
< p > 注释仅仅简单的总结了类型转换做了什么，所以不要太随便的使用。在你的项目使用它们之前，你最好看看它们的详细说明书。< / p >
< p > 尽管写了一些，但我这里不是想给你一个关于< em > type traits< / em > 使用的教程。注意类型转换尾部的< code > ::type< / code > 。如果你在一个模板内部将他们施加到类型形参上（实际代码中你也总是这么用），你也需要在它们前面加上< code > typename< / code > 。至于为什么要这么做是因为这些C++11的< em > type traits< / em > 是通过在< code > struct< / code > 内嵌套< code > typedef< / code > 来实现的。是的，它们使用类型同义词（译注：根据上下文指的是使用< code > typedef< / code > 的做法）技术实现，而正如我之前所说这比别名声明要差。< / p >
< p > 关于为什么这么实现是有历史原因的， （ ） ， ， ： < code > std::< / code > transformation< code > < T> ::type< / code > 在C++14中变成了< code > std::< / code > transformation< code > _t< / code > 。举个例子或许更容易理解：< / p >
< pre > < code class = "language-cpp" > std::remove_const< T> ::type //C++11: const T → T
std::remove_const_t< T> //C++14 等价形式
std::remove_reference< T> ::type //C++11: T& /T& & → T
std::remove_reference_t< T> //C++14 等价形式
std::add_lvalue_reference< T> ::type //C++11: T → T&
std::add_lvalue_reference_t< T> //C++14 等价形式
< / code > < / pre >
< p > C++11的的形式在C++14中也有效， ， ， ， ？ ， ， ： < / p >
< pre > < code class = "language-cpp" > template < class T>
using remove_const_t = typename remove_const< T> ::type;
template < class T>
using remove_reference_t = typename remove_reference< T> ::type;
template < class T>
using add_lvalue_reference_t =
typename add_lvalue_reference< T> ::type;
< / code > < / pre >
< p > 看见了吧？不能再简单了。< / p >
< p > < strong > 请记住：< / strong > < / p >
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< li > < code > typedef< / code > 不支持模板化，但是别名声明支持。< / li >
< li > 别名模板避免了使用“< code > ::type< / code > ”后缀，而且在模板中使用< code > typedef< / code > 还需要在前面加上< code > typename< / code > < / li >
< li > C++14提供了C++11所有< em > type traits< / em > 转换的别名声明版本< / li >
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