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< title > Item 29:认识移动操作的缺点 - Effective Modern C++< / title >
2022-06-30 10:23:03 +08:00
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< ol class = "chapter" > < li class = "chapter-item expanded " > < a href = "../Introduction.html" > 简介< / a > < / li > < li class = "chapter-item expanded " > < div > 第一章 类型推导< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item1.html" > Item 1:理解模板类型推导< / a > < / li > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item2.html" > Item 2:理解auto类型推导< / a > < / li > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item3.html" > Item 3:理解decltype< / a > < / li > < li class = "chapter-item expanded " > < a href = "../1.DeducingTypes/item4.html" > Item 4:学会查看类型推导结果< / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第二章 auto< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../2.Auto/item5.html" > Item 5:优先考虑auto而非显式类型声明< / a > < / li > < li class = "chapter-item expanded " > < a href = "../2.Auto/item6.html" > Item 6:auto推导若非己愿, 使用显式类型初始化惯用法< / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第三章 移步现代C++< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item7.html" > Item 7:区别使用()和{}创建对象< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item8.html" > Item 8:优先考虑nullptr而非0和NULL< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item9.html" > Item 9:优先考虑别名声明而非typedefs< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item10.html" > Item 10:优先考虑限域枚举而非未限域枚举< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item11.html" > Item 11:优先考虑使用deleted函数而非使用未定义的私有声明< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item12.html" > Item 12:使用override声明重载函数< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item13.html" > Item 13:优先考虑const_iterator而非iterator< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item14.html" > Item 14:如果函数不抛出异常请使用noexcept< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item15.html" > Item 15:尽可能的使用constexpr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item16.html" > Item 16:让const成员函数线程安全< / a > < / li > < li class = "chapter-item expanded " > < a href = "../3.MovingToModernCpp/item17.html" > Item 17:理解特殊成员函数函数的生成< / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第四章 智能指针< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item18.html" > Item 18:对于独占资源使用std::unique_ptr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item19.html" > Item 19:对于共享资源使用std::shared_ptr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item20.html" > Item 20:当std::shard_ptr可能悬空时使用std::weak_ptr< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item21.html" > Item 21:优先考虑使用std::make_unique和std::make_shared而非new< / a > < / li > < li class = "chapter-item expanded " > < a href = "../4.SmartPointers/item22.html" > Item 22:当使用Pimpl惯用法, 请在实现文件中定义特殊成员函数< / a > < / li > < / ol > < / li > < li class = "chapter-item expanded " > < div > 第五章 右值引用,移动语义,完美转发< / div > < / li > < li > < ol class = "section" > < li class = "chapter-item expanded " > < a href = "../5.RRefMovSemPerfForw/item23.html" > Item 23:理解std::move和std::forward< / a > < / li > < li class = "chapter-item expanded " > < a href = "../5.RRefMovSemPerfForw/item24.html" > Item 24:区别通用引用和右值引用< / a > < / li > < li class = "chapter-item expanded " > < a href = "../5.RRefMovSemPerfForw/item25.html" > Item 25:对于右值引用使用std::move, 对于通用引用使用std::forward< / a > < / li > < li class = "chapter-item expanded " > < a href = "../5.RRefMovSemPerfF
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< h2 id = "条款二十九假定移动操作不存在成本高未被使用" > < a class = "header" href = "#条款二十九假定移动操作不存在成本高未被使用" > 条款二十九:假定移动操作不存在,成本高,未被使用< / a > < / h2 >
< p > < strong > Item 29: Assume that move operations are not present, not cheap, and not used< / strong > < / p >
< p > 移动语义可以说是C++11最主要的特性。你可能会见过这些类似的描述“移动容器和拷贝指针一样开销小”, “拷贝临时对象现在如此高效, 写代码避免这种情况简直就是过早优化”。这种情绪很容易理解。移动语义确实是这样重要的特性。它不仅允许编译器使用开销小的移动操作代替大开销的复制操作, 而且默认这么做( 当特定条件满足的时候) 。以C++98的代码为基础, 使用C++11重新编译你的代码, 然后, 哇, 你的软件运行的更快了。< / p >
< p > 移动语义确实可以做这些事,这把这个特性封为一代传说。但是传说总有些夸大成分。这个条款的目的就是给你泼一瓢冷水,保持理智看待移动语义。< / p >
< p > 让我们从已知很多类型不支持移动操作开始这个过程。为了升级到C++11, C++98的很多标准库做了大修改, 为很多类型提供了移动的能力, 这些类型的移动实现比复制操作更快, 并且对库的组件实现修改以利用移动操作。但是很有可能你工作中的代码没有完整地利用C++11。对于你的应用中( 或者代码库中) 的类型, 没有适配C++11的部分, 编译器即使支持移动语义也是无能为力的。的确, C++11倾向于为缺少移动操作的类生成它们, 但是只有在没有声明复制操作, 移动操作, 或析构函数的类中才会生成移动操作( 参考< a href = "https://github.com/kelthuzadx/EffectiveModernCppChinese/blob/master/3.MovingToModernCpp/item17.md" > Item17< / a > ) 。数据成员或者某类型的基类禁止移动操作( 比如通过delete移动操作, 参考< a href = "https://github.com/kelthuzadx/EffectiveModernCppChinese/blob/master/3.MovingToModernCpp/item11.md" > Item11< / a > ) , 编译器不生成移动操作的支持。对于没有明确支持移动操作的类型, 并且不符合编译器默认生成的条件的类, 没有理由期望C++11会比C++98进行任何性能上的提升。< / p >
< p > 即使显式支持了移动操作, 结果可能也没有你希望的那么好。比如, 所有C++11的标准库容器都支持了移动操作, 但是认为移动所有容器的开销都非常小是个错误。对于某些容器来说, 压根就不存在开销小的方式来移动它所包含的内容。对另一些容器来说, 容器的开销真正小的移动操作会有些容器元素不能满足的注意条件。< / p >
< p > 考虑一下< code > std::array< / code > , 这是C++11中的新容器。< code > std::array< / code > 本质上是具有STL接口的内置数组。这与其他标准容器将内容存储在堆内存不同。存储具体数据在堆内存的容器, 本身只保存了指向堆内存中容器内容的指针( 真正实现当然更复杂一些, 但是基本逻辑就是这样) 。这个指针的存在使得在常数时间移动整个容器成为可能, 只需要从源容器拷贝保存指向容器内容的指针到目标容器, 然后将源指针置为空指针就可以了: < / p >
< pre > < code class = "language-cpp" > std::vector< Widget> vm1;
//把数据存进vw1
…
//把vw1移动到vw2。以常数时间运行。只有vw1和vw2中的指针被改变
auto vm2 = std::move(vm1);
< / code > < / pre >
< p > < img src = "media/item29_fig1.png" alt = "item29_fig1" / > < / p >
< p > < code > std::array< / code > 没有这种指针实现,数据就保存在< code > std::array< / code > 对象中:< / p >
< pre > < code class = "language-cpp" > std::array< Widget, 10000> aw1;
//把数据存进aw1
…
//把aw1移动到aw2。以线性时间运行。aw1中所有元素被移动到aw2
auto aw2 = std::move(aw1);
< / code > < / pre >
< p > < img src = "media/item29_fig2.png" alt = "item29_fig2" / > < / p >
< p > 注意< code > aw1< / code > 中的元素被< strong > 移动< / strong > 到了< code > aw2< / code > 中。假定< code > Widget< / code > 类的移动操作比复制操作快,移动< code > Widget< / code > 的< code > std::array< / code > 就比复制要快。所以< code > std::array< / code > 确实支持移动操作。但是使用< code > std::array< / code > 的移动操作还是复制操作都将花费线性时间的开销,因为每个容器中的元素终归需要拷贝或移动一次,这与“移动一个容器就像操作几个指针一样方便”的含义相去甚远。< / p >
< p > 另一方面,< code > std::string< / code > 提供了常数时间的移动操作和线性时间的复制操作。这听起来移动比复制快多了,但是可能不一定。许多字符串的实现采用了小字符串优化(< em > small string optimization< / em > , SSO) 。“小”字符串( 比如长度小于15个字符的) 存储在了< code > std::string< / code > 的缓冲区中,并没有存储在堆内存,移动这种存储的字符串并不必复制操作更快。< / p >
< p > SSO的动机是大量证据表明, 短字符串是大量应用使用的习惯。使用内存缓冲区存储而不分配堆内存空间, 是为了更好的效率。然而这种内存管理的效率导致移动的效率并不必复制操作高, 即使一个半吊子程序员也能看出来对于这样的字符串, 拷贝并不比移动慢。< / p >
< p > 即使对于支持快速移动操作的类型,某些看似可靠的移动操作最终也会导致复制。< a href = "https://github.com/kelthuzadx/EffectiveModernCppChinese/blob/master/3.MovingToModernCpp/item14.md" > Item14< / a > 解释了原因, 标准库中的某些容器操作提供了强大的异常安全保证, 确保依赖那些保证的C++98的代码在升级到C++11且仅当移动操作不会抛出异常, 从而可能替换操作时, 不会不可运行。结果就是, 即使类提供了更具效率的移动操作, 而且即使移动操作更合适( 比如源对象是右值) , 编译器仍可能被迫使用复制操作, 因为移动操作没有声明< code > noexcept< / code > 。< / p >
< p > 因此, 存在几种情况, C++11的移动语义并无优势: < / p >
< ul >
< li > < strong > 没有移动操作< / strong > :要移动的对象没有提供移动操作,所以移动的写法也会变成复制操作。< / li >
< li > < strong > 移动不会更快< / strong > :要移动的对象提供的移动操作并不比复制速度更快。< / li >
< li > < strong > 移动不可用< / strong > :进行移动的上下文要求移动操作不会抛出异常,但是该操作没有被声明为< code > noexcept< / code > 。< / li >
< / ul >
< p > 值得一提的是,还有另一个场景,会使得移动并没有那么有效率:< / p >
< ul >
< li > < strong > 源对象是左值< / strong > :除了极少数的情况外(例如< a href = "https://github.com/kelthuzadx/EffectiveModernCppChinese/blob/master/5.RRefMovSemPerfForw/item25.md" > Item25< / a > ),只有右值可以作为移动操作的来源。< / li >
< / ul >
< p > 但是该条款的标题是假定移动操作不存在, 成本高, 未被使用。这就是通用代码中的典型情况, 比如编写模板代码, 因为你不清楚你处理的具体类型是什么。在这种情况下, 你必须像出现移动语义之前那样, 像在C++98里一样保守地去复制对象。“不稳定的”代码也是如此, 即那些由于经常被修改导致类型特性变化的源代码。< / p >
< p > 但是,通常,你了解你代码里使用的类型,依赖他们的特性不变性(比如是否支持快速移动操作)。这种情况,你无需这个条款的假设,只需要查找所用类型的移动操作详细信息。如果类型提供了快速移动操作,并且在调用移动操作的上下文中使用对象,可以安全的使用快速移动操作替换复制操作。< / p >
< p > < strong > 请记住:< / strong > < / p >
< ul >
< li > 假定移动操作不存在,成本高,未被使用。< / li >
< li > 在已知的类型或者支持移动语义的代码中,就不需要上面的假设。< / li >
< / ul >
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< script src = "../highlight.js" type = "text/javascript" charset = "utf-8" > < / script >
< script src = "../book.js" type = "text/javascript" charset = "utf-8" > < / script >
<!-- Custom JS scripts -->
< / body >
< / html >